標題:
實用方程式(已更新2009-8-19)
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作者:
johnny19931993
時間:
2007-8-12 02:00 AM
標題:
實用方程式(已更新2009-8-19)
估唔到我走左咁耐,呢個post仲喺度
之前因爲電腦壞左,所以冇上黎一排
而家上番黎,即刻更新呢個post先
實用方程式:
[hr]red[/hr]生物學:
光合作用 :6H
2
O(水)+ 6CO
2
(二氧化碳)= C
6
H
12
O
6(葡萄糖) +
6O
2
(氧氣)+ Energy
呼吸作用:C
6
H
12
O
6(葡萄糖) +
6O
2
(氧氣)= 6H
2
O(水)+ 6CO
2
(二氧化碳) [注:此過程會釋放出名為ATP的能量,即adenosine triphosphate(三磷酸腺苷)]
[hr]red[/hr]物理學:
密度:density(密度) = mass(重量) / volume(容量)
能量 : Energy(能量) = mass(重量) X Celeritas^2(光速^2) [注:Celeritas是拉丁文,在這條方程式上代表真空光速的來源。]
力量:force(力量) = mass(質量) x acceleration(加速度)
加速度 : acceleration(加速度) = mass(重量) / speed^2(速度^2)
速度: speed(速度) = distance(距離) / time(時間)
[hr]red[/hr]化學:
化學風化:HCl(含微酸的雨水)+ CaCO
3
(石)= H
2
O(水)+ 6CO
2
(二氧化碳)+ CaCl (鹽)
mass = number of moles x molar mass
Avogadro's constant = 6.02 x 10^23
Number of particles/atoms = number of moles x Avogradro's constant
Molecular formula = number of moles x empirical formula
Percentage yield = (actual yield / theoretical yield) x 100%
Initial concentration x initial volume = final concentration x final volume
Molar concentration (mol/L) = amount of solute (mol) x volume of solution (L)
Ideal gas law : PV = nRT
P: Pressure, V: volume, n: number of moles, T: temperature (in Kelvin)
R: Ideal gas constant
[hr]red[/hr]數學:
Equation of line : General Form : Ax + By + C = 0
Point slope form : y - y1 = m(x - x1) , m = slope(斜率)
Two point form : y - y1/x - x1 = y2 - y1/x2 - x1
Slope intercept point : y = mx + b , m = slope(斜率), b = y-intercpet(截段)
Quadratic equation : ax^2 + bx + c
Quadratic formula :
± represents "plus or minus" ( ± 代表" 正或負")
Intercept form : x/a + y/b = 1 , a = -A/C , b = -B/C (A,B,C in general form)
Length of line(線的長度) : Sq root(平方根) of (x1 - x2)^2 + (y1 - y2)^2
Midpoint of line(線的中點) : x = (x1 + x2)/2 , y = (y1 + y2)/2
Slope of line(線的斜率) : slope(斜率) = rise/run
[hr]red[/hr]Trignomotry(三角學):
SineA = Opposite/Hypotensue
CosineA = Adjacent/Hypotensue
TangentA = Opposite/Adjacent = sinA/cosA
[hr]red[/hr]Law of Sine :(Sin A)/a = (Sin B)/b = (Sin C)/c
Law of Cosine :a^2 = b^2 + c^2 - [2bc(cos A)]
b^2 = a^2 + c^2 - [2ac(cos B)]
c^2 = a^2 + b^2 - [2ab(cos C)]
Law of Tangent : (a + b)/(a - b) = tan[0.5(α - β)] / tan[0.5(α + β)]
[
本帖最後由 johnny19931993 於 2009-8-20 11:10 AM 編輯
]
作者:
福耳魔D
時間:
2007-8-23 07:26 PM
實用???
作者:
johnny19931993
時間:
2007-12-9 01:05 PM
推一推先
大家睇下啦,加左好多野呀
作者:
BennyChung
時間:
2007-12-9 01:07 PM
其實係中幾程度...
我小六咋 =.=
作者:
johnny19931993
時間:
2007-12-10 01:37 AM
QUOTE:
原帖由
benny
於 2007-12-9 01:07 PM 發表。
其實係中幾程度...
我小六咋 =.=
加拿大既Grade 9,即係香港既中三,但係始終係外國,程度可能會有o的唔同
作者:
XDD
時間:
2008-1-4 08:15 PM
才中二- -
不明白=口=
作者:
`mR.H0
時間:
2008-3-29 09:49 AM
真深奧.囧
聞所未聞
作者:
kukucat
時間:
2008-4-1 07:07 PM
推推=]*
唔係呢...
好多中1.2都學左呢....
作者:
Hail少
時間:
2008-4-2 10:45 PM
標題:
回覆 #5 johnny19931993 的帖子
Thank you very much!!!
You help me a lot ~~~ ^ ^
CaCO3(石)
我想問CaCO3是指是石的成分/simpler form?
另外,
why 要係d CO2 ar~ O2 ar~ 前面加
6
??
p.s. 我中2 but interest in MAths and Science (espeically in Physic!!! ^ ^)
作者:
johnny19931993
時間:
2008-4-5 04:04 AM
QUOTE:
原帖由
Hail少
於 2008-4-2 10:45 PM 發表。
CaCO3(石)
我想問CaCO3是指是石的成分/simpler form?
CaCO3係石灰岩(Limestone)
QUOTE:
原帖由
Hail少
於 2008-4-2 10:45 PM 發表。
另外,
why 要係d CO2 ar~ O2 ar~ 前面加
6
??
因爲此化學反應需要6個CO2分子和6個O2分子作爲reactants
作者:
kelvinNg
時間:
2008-4-6 10:31 AM
物理有冇萬有引力
F=G(M-m/r^2)
作者:
XDD
時間:
2008-4-30 11:53 PM
Law of Sine :(Sin A)/a = (Sin B)/b = (Sin C)/c
Law of Cosine :a^2 = b^2 + c^2 - [2bc(cos A)]
b^2 = a^2 + c^2 - [2ac(cos B)]
c^2 = a^2 + b^2 - [2ab(cos C)]
Law of Tangent : (a + b)/(a - b) = tan[0.5(α - β)] / tan[0.5(α + β)]
唔明呢個= =
解釋下原理,ok?
作者:
johnny19931993
時間:
2008-5-4 05:37 AM
QUOTE:
原帖由
XDD
於 2008-4-30 11:53 PM 發表。
Law of Sine :(Sin A)/a = (Sin B)/b = (Sin C)/c
Law of Cosine :a^2 = b^2 + c^2 -
b^2 = a^2 + c^2 -
c^2 = a^2 + b^2 -
Law of Tangent : ( ...
有圖,只要把適當的數據填入適當的variable,剩下的variable就能計出
作者:
kelvinNg
時間:
2008-6-15 01:21 PM
即係只要有information
跟著sub佢就得???
作者:
hk_people
時間:
2009-8-24 09:46 AM
唔知你up乜-____-
作者:
qweeees123
時間:
2011-6-7 10:02 PM
實用到5明囉
好笑
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